Complex Java Permutation Generation Problem

I am trying to work out the best way to generate all possible permutations for a sequence which is a fixed number of digits and each digit has a dif开发者_JAVA技巧ferent alphabet.

I have a number of integer arrays and each one can have different length and when generating the permutations only the values of the array can occupy the position in the final results.

A specific example is an int array called conditions with the following data:

conditions1 = {1,2,3,4}
conditions2 = {1,2,3}
conditions3 = {1,2,3}
conditions4 = {1,2}
conditions5 = {1,2} 

and I want to create a 5 column table of all the possible permutations - this case 144 (4x3x3x2x2). Column 1 can only use the values from conditions1 and column 2 from conditions2, etc.

output would be :

1,1,1,1,1
1,1,1,1,2
1,1,1,2,1
1,1,1,2,2
1,1,2,1,1
.
.
through to 
4,3,3,2,2

It's been too long since since I've done any of this stuff and most of the information I've found relates to permutations with the same alphabet for all fields. I can use that then run a test after removing all the permutations that have columns with invalid values but sounds inefficient.

I'd appreciate any help here.

Z.

Look ma, no recursion needed.

Iterator<int[]> permutations(final int[]... conditions) {
  int productLengths = 1;
  for (int[] arr : conditions) { productLengths *= arr.length; }
  final int nPermutations = productLengths;
  return new Iterator<int[]>() {
    int index = 0;
    public boolean hasNext() { return index < nPermutations; }
    public int[] next() {
      if (index == nPermutations) { throw new NoSuchElementException(); }
      int[] out = new int[conditions.length];
      for (int i = out.length, x = index; --i >= 0;) {
        int[] arr = conditions[i];
        out[i] = arr[x % arr.length];
        x /= arr.length;
      }
      ++index;
      return out;
    }
    public void remove() { throw new UnsupportedOperationException(); }
  };
}

Wrapping it in an Iterable<int[]> will make it easier to use with a for (... : ...) loop. You can get rid of the array allocation by doing away with the iterator interface and just taking in as argument an array to fill.