How to use Firebug's monitor(fn)?
I read the Firebug documentation about the Command Line API.
Wrote monitor(functionName)
in the command editor and pressed Ctrl+Enter. I can't see anything开发者_如何学Go happening... May be my understanding of this command is completely wrong.
I googled but I am still confused how to use this API command?
Work fine for me...
Check out the example i made at http://fiddle.jshell.net/gaby/LbCYn/show/
Open the console and put monitor(toBeMonitored);
. Now each time you click the button it will put in the console that the method was executed..
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