How to replace a p tag value if a radio is checked?
I want replace a p tag value if a radio is checked.
I write some JS to do this,but nothing changed. this is my code(I use jquery)
<script>
$(functi开发者_如何学运维on(){
if ($('#A:checked')) {
$("#change_me").html('<input type="radio" value="1" name="fruit">')
}
if ($('#B:checked')) {
$("#change_me").html('<input type="radio" value="2" name="fruit">')
}
}
</script>
<input type="radio" name="e" id="A" checked="checked">
<input type="radio" name="e" id="B">
<p id="change_me">
<input type="radio" value="1" name="fruit">
</p>
Thanks.
The :checked
selector matches elements that are currently checked.
Writing $('#B:checked')
returns a jQuery object containing either zero or one element. It cannot be used directly as a condition.
Instead, you can check if ($('#B:checked').length)
to see whether the jQuery object has anything in it.
First, you don't need to recreate the radio button if only the value is changing.
$(function(){
if ($('#A:checked').size() > 0) {
$("#change_me input[type=radio]").val('1')
}
if ($('#B:checked').size() > 0) {
$("#change_me input[type=radio]").val('2')
}
}
HTML:
<input type="radio" name="e" id="A" checked="checked">
<input type="radio" name="e" id="B">
<p id="change_me">
<input type="radio" value="1" name="fruit">
</p>
Replace the JavaScript code you have with the following
$(function(){
$('input[name=e]').change(function(){
if($(this).attr('id') == 'A')
{
$("#change_me input").val('1');
}
else
{
$("#change_me input").val('2');
}
});
});
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