Choosing a random string in C# for WP7

I am making a WP7 app that, when a user taps an image, randomly decides what they will get.

Right now, I have this code:

string firstdoor = "";

string seconddoor = "";

string thirddoor = "";

and

string prize1 = "vacation to Hawaii with all expenses covered";

string prize2 = "used glue stick";

string prize3 = "pile of dog dung";

string prize3 = "vacation to Europe w开发者_运维问答ith all expenses covered";

string prize3 = "million dollars";

string prize3 = "blank CD";

string prize3 = "temporary tattoo";

string prize3 = "nickel";

string prize3 = "dime";

and

What I want to do is randomly assign the doors to the prizes.

For instance, when the user taps the image, dime is assigned to thirddoor, nickel is assigned to firstdoor, and million dollars is assigned to secondoor.

Here are the steps that seem to make the most sense to me (not going to write all the code for you):

1. Put all prize strings in an array.

2. Generate three random numbers between 0 and the maximum number of prizes.

3. Assign each door the prize from the prize array with each of the random numbers.

4. ...

5. Profit!

Edit

Actually, here's a little bit of code to help out:

var randomGenerator = new Random();

string[] prizes = { "vacation to Hawaii with all expenses covered",
                    "used glue stick",
                    "pile of dog dung",
                    "vacation to Europe with all expenses covered" };

string firstDoor = prizes[randomGenerator.Next(prizes.Length)];
string secondDoor = prizes[randomGenerator.Next(prizes.Length)];
string thirdDoor = prizes[randomGenerator.Next(prizes.Length)];

On the assumption that you don't want to repeat any of the prizes the solution is a little more complicated, but you can bring some Linq and a little trick with Random into play:

    var prizes = new string[] {
        "vacation to Hawaii with all expenses covered",
        "used glue stick",
        // etc
        "dime"            
    };

    var rand = new Random();

    var result = (from prize in prizes
                  orderby rand.NextDouble()
                  select prize).Take(3).ToArray();

Justin, your answer is fine but might result in 2 doors having the same prize. I believe this might be better:

string[] prizes = new string[]
        {
            "Prize 1",
            "Prize 2",
            "Prize 3",
            "Prize 4",
            "Prize 5"
        };

        Random r = new Random();
        var choices = prizes.OrderBy(x => r.Next()).Take(3).ToArray();

        string firstDoor = choices[0];
        string secondDoor = choices[1];
        string thirdDoor = choices[2];