How to format bigint field into a date in Postgresql?
I have a table with a field of type bigint. This field store a timestamp. I want to date format the field like this :
开发者_开发问答to_char( bigint_field,'DD/MM/YYYY HH24:MI:SS')
I get the following error :
ERROR: multiple decimal points État SQL :42601
TO_CHAR(TO_TIMESTAMP(bigint_field / 1000), 'DD/MM/YYYY HH24:MI:SS')
This is what worked for me
to_timestamp( bigint_field/1000)::date
This depends on what the bigint value represents - offset of epoch time, or not.
select to_timestamp(20120822193532::text, 'YYYYMMDDHH24MISS')
returns
"2012-08-22 19:35:32+00"
I did it like this:
to_timestamp(to_char(20120822193532, '9999-99-99 99:99:99'),'YYYY-MM-DD HH24:MI:SS')
the result looks like this:
2012-08-22 19:35:32
you also can use this in you select statemant, just exchange the number with your database colunm.
Step by Step Explanation:
to_char(20120822193532, '9999-99-99 99:99:99')
This will create a string like this:
"2012-08-22 19:35:32"
now we can easiely convert this into a timestamp:
to_timestamp('2012-08-22 19:35:32','YYYY-MM-DD HH24:MI:SS')
Result will look the same as before, but it's now a timestamp.
Also, if you use this for a command like
CREATE TABLE table2 AS SELECT to_timestamp(to_char(tb1.date, '9999-99-99 99:99:99'),'YYYY-MM-DD HH24:MI:SS') AS realDate FROM table1 AS tb1;
you might end up with timstamptz (timestamp with time zone) instead of timestamp (timestamp without time zone). You can change it like this:
ALTER TABLE table2 ALTER realDate SET DATA TYPE timestamp USING realDate;
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