PHP and javascript POST
I have the following code:
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.min.js" type="text/javascript">
</script>
<script type="text/javascript">
function displayTweet(){
var i = 0;
var limit = $("#twitter-results > div").size();
var myInterval = window.setInterval(function () {
var element = $("#twitter-results div:last-child");
$("#twitter-results").prepend(element);
element.fadeIn("slow");
i++;
if(i==limit){
window.setTimeout(function () {
clearInterval(myInterval);
});
}
},2000);
}
$("form#twittersearch").submit(function() {
twitterq = $('#twitterq').attr('value');
$.ajax({
type: "POST",
url: "search.php",
cache: false,
data: "twitterq="+ twitterq,
success: function(html){
$("#twitter-results").html(html);
displayTweet();
}
});
return false;
});
});
</script>
</head>
<div class="twitter_container">
<form id="twittersearch" method="post" action="">
<input name="twitterq" type="text" id="twitterq" />
<button type="submit">Search</button>
</form>
<div id="twitter-results"></div>
</div>
</html>
/***************THIS IS search.php***************************/
<?php
include('twitterapi.php');
if($_POST['twitterq']){
$twitter_query = $_POST['twitterq'];
$search = new TwitterSearch($twitter_query);
$results = $search->results();
foreach($results as $result){
echo '<div class="twitter_status">';
echo '<img src="'.$result->profile_image_url.'" class="twitter_image">';
$text_n = toLink($result->text);
echo $t开发者_高级运维ext_n;
echo '<div class="twitter_small">';
echo '<strong>From:</strong> <a href="http://www.twitter.com/'.$result->from_user.'">'.$result->from_user.'</a&glt;: ';
echo '<strong>at:</strong> '.$result->created_at;
echo '</div>';
echo '</div>';
}
}
?>
Why is it that when I do a var_dump($_POST['twitterq']) it is always NULL?
UPDATE:
firebug gave me this, not sure how to fix it though:
That is because you are not providing the data properly. It should be:
data: ({twitterq: twitterq}),
You are sending data in the form of JSON. You are not using URL parameters , so there is no need of '='. if you have more than one parameters, you will simply separate them with commas.
加载中,请稍侯......
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