ignoring header content of a text

I want to get rid of the content of a file before "this word" and only write the lines after that word on to disk.

text = <<EOT
  I only want
  the last lines
  of the file after
  this word. This is
  the content I 
  want. Yet this
  word can appear again.
EOT

puts text.scan("this word")

expected output:

This is
the content I 
want. Yet this
word can appear again.

What is the most efficient way to 开发者_如何学Pythondo this?

Any help appreciated

Ted.

If 'this word' appears only once in your test, or if you want to remove up to the last such phrase:

text.sub(/.*this word\W*/, '')

If there is possibility that 'this word' appears multiple time and you want to remove only up to the first of such:

text.sub(/.*?this word\W*/, '')

Like this?

irb(main):001:0> text = <<EOT
irb(main):002:0"   I only want
irb(main):003:0"   the last lines
irb(main):004:0"   of the file after
irb(main):005:0"   this word. This is
irb(main):006:0"   the content I 
irb(main):007:0"   want.
irb(main):008:0" EOT
=> "  I only want\n  the last lines\n  of the file after\n  this word. This is\n  the content I \n  want.\n"
irb(main):009:0> needle = 'this word. '
=> "this word. "
irb(main):012:0> text[text.index(needle)+needle.length..-1]
=> "This is\n  the content I \n  want.\n"
irb(main):013:0> print text[text.index(needle)+needle.length..-1]
This is
  the content I 
  want.
=> nil

One easy way is to use the partition method:

text.partition("this word. ").last

(this assumes that "this word. " actually appears in the variable text. If it doesn't, an empty string will be returned by this code.)

One way:

text.split('this word. ')[1]

Or

text.split('this word. ').last