Java If Statement
I have written some code in Java which tests the fitness of two solutions.
I am looking to then compare the two solutions and keep the one which has the best fitnes开发者_运维知识库s and to discard the other.
For example:
if(fitness1 < fitness2)
keep fitness1 and discard/ignore fitness2
else
keep fitness2 and discard/ignore fitness1
How would I go about achieving this? Eventually I hope to have a list (size n) of the best fitness levels. I imagine that I would have to add the best fitness in each iteration to a list of some type?
best = (fitness1 < fitness2) ? fitness1 : fitness2;
?:
ternary operator may be useful in this kind of decision making process.
I'd say, create an ArrayList<Double>
to keep the best values in and use this:
arrayList.add((fitness1 < fitness2) ? fitness1 : fitness2);
That way you'll have a list of the best values.
If your end goal is to have a list of the "top n fitness levels", you'll probably have a list of them coming in, right?
If that's the case, just leverage the capabilities of List:
// takes a list of Doubles, returns 'top' levels
public List<Double> getTopN(List<Double> allLevels, int top) {
List<Double> sorted = new ArrayList<Double>(allLevels); // defensive copy
Collections.sort(sorted, new Comparator<Double>() {
@Override
public int compare(Double left, Double right) {
return left.compareTo(right); // assumes no null entries
}
});
return sorted.subList(0, Math.min(sorted.size(), top));
}
Introduce another variable.
type bestFitness
if(fitness1 < fitness2){
bestFitness = fitness1;
}else{
bestFitness = fitness2;
}
Then discard both fitness1
, fitness2
Or use Math.min
Assuming the fitness is an int
int fitness1 = 5;
int fitness2 = 10;
int bestFit = bestFit(fitness1, fitness2);
//nothing needs to be done to explicitly discard fitness2. Just keep using bestFit
//and let the GC worry about discarding stuff for you
public static int bestFit(int f1, int f2) {
return f1 > f2 ? f1 : f2
}
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