Executing only the code of a page?
Hi guys consider I have a .php pa开发者_StackOverflowge that I need to include somewhere else.
page.php:
<?php
dosomecmd();
doothercmd();
//etc
?><html>pagehtml</html>
Is there a way to include this page but not printing the html inside? (I just need to execute those command)
I could do with ob
ob_start();
include('page.php');
ob_discard();
But i would prefer a faster way.
Thanks
Edit: i know i can sepearate html and php (and i already do) but that page.php is non else than a "static" cache I make, but sometimes I need to execute some command inside that cache instead to printing automatically it out
Edit2: of course i don't need everyime to not output the html (otherwise I could just delete all html) I need to return; only based on the results of my cmds up there
Thanks all i find a solution (add return;)
Would it be easier to have a common page with only the php that you need to share, and include it in both page.php and your other page?
you can try to seperate with $_SERVER['REQUEST_URI']
also I wouldn't recommend that
Try to separate the PHP logic at the start of your current script into another file, then include that into both of your scripts.
加载中,请稍侯......
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