Programmatically replace transparent regions in an image with white fill?
I've got a PNG image that I'm operating on via the System.Drawing API in .NET. It has large trans开发者_开发技巧parent regions, and I would like to replace the transparent regions with white fill--so that there are no transparent regions in the image. Easy enough in an image editing program... but so far I've had no success doing this in C#.
Can someone give me some pointers?
I'm not sure how to detect transparent pixel. I know if the Alpha is 0 it's completly transparent and if it's 255 it's opaque. I'm not sure if you should check for Alpha == 0 or Alpha != 255 ; if you can try it and give me a feedback that would be helpful.
From MSDN
The alpha component specifies the transparency of the color: 0 is fully transparent, and 255 is fully opaque. Likewise, an A value of 255 represents an opaque color. An A value from 1 through 254 represents a semitransparent color. The color becomes more opaque as A approaches 255.
void Foo(Bitmap image)
{
for (int y = 0; y < image.Height; ++y)
{
for (int x = 0; x < image.Width; ++x)
{
// not very sure about the condition.
if (image.GetPixel(x, y).A != 255)
{
image.SetPixel(x,y,Color.White);
}
}
}
}
My example:
public void FillPngWhite(Bitmap bmp)
{
if (bmp.PixelFormat != PixelFormat.Format32bppArgb)
throw new ApplicationException("Not supported PNG image!");
// Lock the bitmap's bits.
Rectangle rect = new Rectangle(0, 0, bmp.Width, bmp.Height);
BitmapData bmpData = bmp.LockBits(rect, ImageLockMode.ReadWrite, bmp.PixelFormat);
// Get the address of the first line.
IntPtr ptr = bmpData.Scan0;
// Declare an array to hold the bytes of the bitmap.
int bytes = Math.Abs(bmpData.Stride) * bmp.Height;
byte[] rgbaValues = new byte[bytes];
// Copy the RGB values into the array.
System.Runtime.InteropServices.Marshal.Copy(ptr, rgbaValues, 0, bytes);
// array consists of values RGBARGBARGBA
for (int counter = 0; counter < rgbaValues.Length; counter += 4)
{
double t = rgbaValues[counter + 3]/255.0; // transparency of pixel between 0 .. 1 , easier to do math with this
double rt = 1 - t; // inverted value of transparency
// C = C * t + W * (1-t) // alpha transparency for your case C-color, W-white (255)
// same for each color
rgbaValues[counter] = (byte) (rgbaValues[counter]*t + 255*rt); // R color
rgbaValues[counter + 1] = (byte)(rgbaValues[counter + 1] * t + 255 * rt); // G color
rgbaValues[counter + 2] = (byte)(rgbaValues[counter + 2] * t + 255 * rt); // B color
rgbaValues[counter + 3] = 255; // A = 255 => no transparency
}
// Copy the RGB values back to the bitmap
System.Runtime.InteropServices.Marshal.Copy(rgbaValues, 0, ptr, bytes);
// Unlock the bits.
bmp.UnlockBits(bmpData);
}
This is different bacause:
I use LockBits
instead GetPixel
and SetPixel
. It is much more faster, but little harder to understand. It's a little modified example from : MSDN
I'm taking real aplha value into consideration, as I said in the comment to your question. This will make black with 50% transparency (128) look like gray instead of black. Reason for this is by "replace alpha with white in graphics editor" I imagine creating new layer underneath you image filled with white and then flattening both layers together. This example will have same effect.
Once you have a handle to the bitmap object, just do something like:
Bitmap yourImage = HOWEVER YOU LOAD YOUR IMAGE;
int width = YOUR IMAGE WIDTH;
int height = YOUR IMAGE HEIGHT;
Color c;
Color white = new Color(255,255,255,255)
for(int w = 0; w < width; w++)
for(int h = 0; h < height; h++)
{
c = yourImage.GetPixel(w,h);
yourImage.SetPixel(w,h, ((((short)(c.A)) & 0x00FF) <= 0)? white:c); //replace 0 here with some higher tolerance if needed
}
This may be oversimplifying your problem, but if it's on a form or other readily available control, you could simply paint the background White before placing the Image on top.
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