const char to char problem

How do I convert from char to const char? How do I implement type casting without changing the char SendBuf? Here is my code:

.cpp

// main()    
char SendBuf[6] = "Hello";
sendto(..., SendBuf, ...);

// sendto structure
int sen开发者_StackOverflow中文版dto(
__in  SOCKET s,
__in  const char *buf,
__in  int len,
__in  int flags,
__in  const struct sockaddr *to,
__in  int tolen
);

Error

Error   1   error C2440: '=' : cannot convert from 'const char [6]' to 'char [6]'

Thank you.

I don't have a Microsoft compiler handy to test this theory, but I suspect that the OP has code like this:

int main() {
    char SendBuf[6];
    SendBuf = "Hello";
    // sendto(..., SendBuf, ...);
}

I suspect that the error he is seeing, cannot convert from 'const char [6]' to 'char [6]' is occuring on assignment, not initialization nor the sendto call.

Can someone with a Microsoft compiler check compile the above program and confirm the error message?

Write the assignment like this:

const char *SendBuf = "Hello";

You don't have to do anything about the function call. (A const char* parameter will take a char* variable as input.)

Try

char SendBuf[6] = { "Hello" };

Note the braces, which tell the compiler you're initializing an aggregate (in this case an array).

And then, instead of

SendBuf = "Hello";

which is obviously your real code, use

strcpy(SendBuf, "Hello");

or

memcpy(SendBuf, "Hello", 6);

Is there a reason why you can't pass your string literal into the method? sendTo(...,"Hello",...);

If yes then why not simple declare const char* SendBuf = "Hello"; instead of using the char array as one alternative.

Or perhaps better yet start exploring STL and use std::string SendBuf("Hello"); and pass SendBuf.c_str() into the method.

There is always more than one way to skin a cat just pick the knife that is most comfortable for you.