Overload output operator in a enum in C++
Its posible to overload th开发者_StackOverflow中文版e output operator inside an enum ? I'm getting all sort of errors(if I use class, I dont get any):
../src/oop.cpp:18:2: error: expected identifier before 'friend'
../src/oop.cpp:18:2: error: expected '}' before 'friend'
../src/oop.cpp:18:2: error: 'friend' used outside of class
../src/oop.cpp:18:16: error: expected initializer before '&' token
../src/oop.cpp:22:1: error: expected declaration before '}' token
I'm after to implement something like this(java code):
public enum Type {
ACOUSTIC, ELECTRIC;
public String toString() {
switch(this) {
case ACOUSTIC: return "acoustic";
case ELECTRIC: return "electric";
default: return "unspecified";
}
}
}
Thank you.
edit:
enum Type {
//ACOUSTIC, ELECTRIC;
inline std::ostream& operator << (std::ostream& os, Type t) // error here
{
}
};
enum MyEnum {
foo, bar
};
inline std::ostream & operator<<(std::ostream & Str, MyEnum V) {
switch (V) {
case foo: return Str << "foo";
case bar: return Str << "bar";
default: return Str << (int) V;
}
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