开发者

bash merge multiple lines

I have a file looks like:

id001 success:100
id002 success:99
id002 failed:1
id003 failed:100
id004 success:50
id004 failed:50

I want to format it as:

id001 succe开发者_Python百科ss:100
id002 success:99 failed:1
id003 failed:100
id004 success:50 failed:50

Could someone give me a solution? Thanks!


awk '{a[$1]=a[$1] FS $2}END{for(i in a) print i,a[i]}' file

Alternative Ruby(1.9+)

$ ruby -ane 'BEGIN{a=Hash.new};a[$F[0]]="#{a[$F[0]]} #{$F[1]}"; END{ a.each{|x,y| puts "#{x}#{y}" }}' file


Using 'awk':

awk '{line[$1] = line[$1] " " $2}
     END { for (id in line) { printf "%s%s\n", id, line[id] } }'


It's short (but cryptic) in sed:

sed '$!N;/^\([^ ]*\) .*\n\1/{s/\n[^ ]* / /;};P;D' file


Without using awk (just for the fun of it):

for i in `grep -o "id[0-9]*" myfile`; do
   echo -n "$i "
   grep $i myfile | cut -c 7- |xargs
done | uniq


Didn't see any Perl answers. So here you go:

perl -lnae '$h{$F[0]}.="$F[1] ";END{print "$_ $h{$_}"for(sort keys %h)}' file

See it on Ideone

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜