Removing the </p> tag from grep output

I have I bash script that will find phones numbers inside .htm or .html files in a directory (or recursivly down if I want it) to find phone numbers in the format (ddd)ddd-dddd or ddd-ddd-dddd (Where d represents a digit).

This is my code:

find ./ -maxdepth 1 -regex ".*\(html\|htm\)$" | xargs grep '\(([0-9]\{3\})\|[0-9]\{3\}\)[-]\?[0-9]\{3\}-[0-9]\{4\}'

The output is:

./dash_only_phone.htm:800-555-1212</p>
./paren_phone.htm:(800)555-1212</p>

I was wondering how I wou开发者_C百科ld change the grep command to remove the html p tag printout at the end.

Thanks,

If your grep supports Perl Compatible Regular Expressions, as do GNU and OS X grep:

grep -Po '(\([0-9]{3}\)|[0-9]{3})-?[0-9]{3}-[0-9]{4}(?=</p>)'

Note the changes in escaping (which are similar to or the same as for grep -E).

Why not just pass the output through a sed filter to remove it, as in the following transcript:

pax$ echo './dash_only_phone.htm:800-555-1212</p>' | sed 's?</p>$??'
./dash_only_phone.htm:800-555-1212

This will get rid of any </p> sequences that appear at the end of a line.

You can just add the -o switch to get the IP

find ./ -maxdepth 1 -regex ".*\(html\|htm\)$" | xargs grep -o '\(([0-9]\{3\})\|[0-9]\{3\}\)[-]\?[0-9]\{3\}-[0-9]\{4\}'