Unexpected $end: I Know exactly where the culprit is, but don't know how to fix it
I get this error message:
"Parse error: syntax error, unexpected $end in C:\Users\Stacky\Desktop\xampp\htdocs\wweff\stackhelp.php on line 822"
I've been trying to get this code working by tinkering with only one line of my code, line 54.
Here's the full code. Look out for "//^^^^ RIGHT ABOVE IS LINE 54." in the code below:
<html>
<head>
</head>
<body>
<?php
$objConnect = mysql_connect("localhost","root","") or die(mysql_error());
$objDB = mysql_select_db("thegoodhumor");
$strSQL = "SELECT * FROM gallery";
if (!isset($_GET['Page'])) $_GET['Page']='0';
$objQuery = mysql_query($strSQL);
$Num_Rows = mysql_num_rows($objQuery);
$Per_Page = 16; // Per Page
$Page = $_GET["Page"];
if(!$_GET["Page"])
{
$Page=1;
}
$Prev_Page = $Page-1;
$Next_Page = $Page+1;
$Page_Start = (($Per_Page*$Page)-$Per_Page);
if($Num_Rows<=$Per_Page)
{
$Num_Pages =1;
}
else if(($Num_Rows % $Per_Page)==0)
{
$Num_Pages =($Num_Rows/$Per_Page) ;
}
else
{
$Num_Pages =($Num_Rows/$Per_Page)+1;
$Num_Pages = (int)$Num_Pages;
}
开发者_如何学编程 $strSQL .=" order by GalleryID ASC LIMIT $Page_Start , $Per_Page";
$objQuery = mysql_query($strSQL);
$cell = 0;
echo '<table border="1" cellpadding="2" cellspacing="1"><tr>';
while($objResult = mysql_fetch_array($objQuery))
{
if($cell % 4 == 0) {
echo '</tr><tr>';
}
if($cell == 2 || $cell == 3) {
echo '<td>RESERVED</td>';
} else {
echo '<td><img src="https://s3.amazonaws.com/imagetitle/' .
$objResult["Picture"];?>" height="190" width="190" /> . .$objResult["GalleryName"].'\</td>';
//^^^^ RIGHT ABOVE IS LINE 54.
}
$cell++;
}
echo '</tr></table>';
?>
<?php
//DELETED PAGINATION CODE for the sake of simplicity in StackOverflow
?>
</body>
</html>
<?php
mysql_close($objConnect);
?>
$objResult["Picture"];?>" height="190" width="190" /> . .$objResult["GalleryName"].'\</td>';
Contains ?>, which tells the PHP interpreter to stop interpreting, in other words everything that follows is raw HTML.
Try changing the ;?> to a ., putting a ` before height="190", and remove the \ before </td>, giving:
$objResult["Picture"] . 'height="190" width="190" />' .
$objResult["GalleryName"] . '</td>';
You have "?>" in the middle of line 54, which tells PHP to stop pre-processing (in the middle of your echo statement). You probably want to remove that.
In the following portion of code :
while($objResult = mysql_fetch_array($objQuery))
{
if($cell % 4 == 0) { // A { is opened here
echo '</tr><tr>';
// Maybe it should be closed here ?
}
It seems you are not closing the { that corresponds to the if.
And, a bit lower in your code, you have a } that doesn't seem to belong there :
if($cell == 2 || $cell == 3) {
echo '<td>RESERVED</td>';
} else {
echo '<td><img src="https://s3.amazonaws.com/imagetitle/' .
$objResult["Picture"];?>" height="190" width="190" /> . .$objResult["GalleryName"].'\</td>';
//^^^^ RIGHT ABOVE IS LINE 54.
} // closing the else
$cell++;
} // what is this doing here ?
General advice in this kind of situation : indent your code properly !
This will allow you to catch this kind of problems far more easily ;-)
And will make your code easier to read, of course.
加载中,请稍侯......
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