Call a function with 'arguments' as separate arguments

I'm trying to pass the arguments variable of a function as separate arguments to another function. I tried this:

functio开发者_运维知识库n call_function(func) {
    func(arguments);
}

However, call_function(someFunction, 123, 456) actually calls someFunction([someFunction, 123, 456]). Regardless of the function itself being passed, it is passed as an Arguments object/array-like thing, but I'd rather call the function in this case as someFunction(123, 456).

What I also tried is: func(Array.prototype.slice.call(arguments, 1)) to remove the function (first argument), but obviously this actually returns an array, i.e. it passes the array as the first argument to the function.

How could I code call_function so that a call like call_function(someFunction, 123, 456) results in someFunction(123, 456) being called?

You can use the apply function to call a function with the array as arguments. https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Function/apply