Remove local git tags that are no longer on the remote repository
We use tags in git as part of our deployment proce开发者_JS百科ss. From time to time, we want to clean up these tags by removing them from our remote repository.
This is pretty straightforward. One user deletes the local tag and the remote tag in one set of commands. We have a little shell script that combines both steps.
The 2nd (3rd, 4th,...) user now has local tags that are no longer reflected on the remote.
I am looking for a command similar to git remote prune origin
which cleans up locally tracking branches for which the remote branch has been deleted.
Alternatively, a simple command to list remote tags could be used to compare to the local tags returned via git tag -l
.
This is great question, I'd been wondering the same thing.
I didn't want to write a script so sought a different solution. The key is discovering that you can delete a tag locally, then use git fetch to "get it back" from the remote server. If the tag doesn't exist on the remote, then it will remain deleted.
Thus you need to type two lines in order:
git tag -l | xargs git tag -d
git fetch --tags
These:
Delete all tags from the local repo. FWIW, xargs places each tag output by "tag -l" onto the command line for "tag -d". Without this, git won't delete anything because it doesn't read stdin (silly git).
Fetch all active tags from the remote repo.
This even works a treat on Windows.
From Git v1.7.8 to v1.8.5.6, you can use this:
git fetch <remote> --prune --tags
Update
This doesn't work on newer versions of git (starting with v1.9.0) because of commit e66ef7ae6f31f2. I don't really want to delete it though since it did work for some people.
As suggested by "Chad Juliano", with all Git version since v1.7.8, you can use the following command:
git fetch --prune <remote> +refs/tags/*:refs/tags/*
You may need to enclose the tags part with quotes (on Windows for example) to avoid wildcard expansion:
git fetch --prune <remote> "+refs/tags/*:refs/tags/*"
Looks like recentish versions of Git (I'm on git v2.20) allow one to simply say
git fetch --prune --prune-tags
Much cleaner!
https://git-scm.com/docs/git-fetch#_pruning
You can also configure git to always prune tags when fetching:
git config fetch.pruneTags true
If you only want to prune tags when fetching from a specific remote, you can use the remote.<remote>.pruneTags
option. For example, to always prune tags when fetching from origin but not other remotes,
git config remote.origin.pruneTags true
If you only want those tags which exist on the remote, simply delete all your local tags:
$ git tag -d $(git tag)
And then fetch all the remote tags:
$ git fetch --tags
All versions of Git since v1.7.8 understand git fetch
with a refspec, whereas since v1.9.0 the --tags
option overrides the --prune
option. For a general purpose solution, try this:
$ git --version
git version 2.1.3
$ git fetch --prune origin "+refs/tags/*:refs/tags/*"
From ssh://xxx
x [deleted] (none) -> rel_test
For further reading on how the "--tags" with "--prune" behavior changed in Git v1.9.0, see: https://github.com/git/git/commit/e66ef7ae6f31f246dead62f574cc2acb75fd001c
Good question. :) I don't have a complete answer...
That said, you can get a list of remote tags via git ls-remote
. To list the tags in the repository referenced by origin
, you'd run:
git ls-remote --tags origin
That returns a list of hashes and friendly tag names, like:
94bf6de8315d9a7b22385e86e1f5add9183bcb3c refs/tags/v0.1.3
cc047da6604bdd9a0e5ecbba3375ba6f09eed09d refs/tags/v0.1.4
...
2f2e45bedf67dedb8d1dc0d02612345ee5c893f2 refs/tags/v0.5.4
You could certainly put together a bash script to compare the tags generated by this list with the tags you have locally. Take a look at git show-ref --tags
, which generates the tag names in the same form as git ls-remote
).
As an aside, git show-ref
has an option that does the opposite of what you'd like. The following command would list all the tags on the remote branch that you don't have locally:
git ls-remote --tags origin | git show-ref --tags --exclude-existing
In new git versions (like v2.26.2 or higher) you could use --prune-tags
-P
--prune-tags
Before fetching, remove any local tags that no longer exist on the remote if--prune
is enabled. This option should be used more carefully, unlike--prune
it will remove any local references (local tags) that have been created. This option is a shorthand for providing the explicit tag refspec along with--prune
, see the discussion about that in its documentation.
So you would need to run:
git fetch origin --prune --prune-tags
Git natively supports cleanup of local tags
git fetch --tags --prune-tags
This command pulls in the latest tags and removes all deleted tags
I know I'm late to the party, but now there's a quick answer to this:
git fetch --prune --prune-tags # or just git fetch -p -P
Yes, it's now an option to fetch.
If you don't want to fetch, and just prune:
git remote prune origin
this is a good method:
git tag -l | xargs git tag -d && git fetch -t
Source: demisx.GitHub.io
Updated @2021/05
Pass $REPO
parameter to custom script.
The content of sync_git_tags.sh
#!/bin/sh
# cd to $REPO directory
cd $1
pwd
# sync remote tags
git tag -l | xargs git tag -d && git fetch -t
Old
ps: updated @2021/05,
git fetch --prune --prune-tags origin
not working in my MacOS.
I add the command to SourceTree
as a Custom Action on my MacOS.
Setting Custom Actions
by Sourcetree
-> Preferences...
-> Custom Actions
`Script to run` have to be the `git` path.
I use git fetch --prune --prune-tags origin
to sync tags from remote to local.
The same answer as @Richard W but for Windows (PowerShell)
git tag | ForEach-Object -Process { git tag -d $_ }
git fetch -t
Show the difference between local and remote tags:
diff <(git tag | sort) <( git ls-remote --tags origin | cut -f2 | grep -v '\^' | sed 's#refs/tags/##' | sort)
git tag
gives the list of local tagsgit ls-remote --tags
gives the list of full paths to remote tagscut -f2 | grep -v '\^' | sed 's#refs/tags/##'
parses out just the tag name from list of remote tag paths- Finally we sort each of the two lists and diff them
The lines starting with "< " are your local tags that are no longer in the remote repo. If they are few, you can remove them manually one by one, if they are many, you do more grep-ing and piping to automate it.
Just added a git sync-local-tags command to pivotal_git_scripts Gem fork on GitHub:
https://github.com/kigster/git_scripts
Install the gem, then run "git sync-local-tags" in your repository to delete the local tags that do not exist on the remote.
Alternatively you can just install this script below and call it "git-sync-local-tags":
#!/usr/bin/env ruby
# Delete tags from the local Git repository, which are not found on
# a remote origin
#
# Usage: git sync-local-tags [-n]
# if -n is passed, just print the tag to be deleted, but do not
# actually delete it.
#
# Author: Konstantin Gredeskoul (http://tektastic.com)
#
#######################################################################
class TagSynchronizer
def self.local_tags
`git show-ref --tags | awk '{print $2}'`.split(/\n/)
end
def self.remote_tags
`git ls-remote --tags origin | awk '{print $2}'`.split(/\n/)
end
def self.orphaned_tags
self.local_tags - self.remote_tags
end
def self.remove_unused_tags(print_only = false)
self.orphaned_tags.each do |ref|
tag = ref.gsub /refs\/tags\//, ''
puts "deleting local tag #{tag}"
`git tag -d #{tag}` unless print_only
end
end
end
unless File.exists?(".git")
puts "This doesn't look like a git repository."
exit 1
end
print_only = ARGV.include?("-n")
TagSynchronizer.remove_unused_tags(print_only)
How about this - drop all local tags and then re-fetch? Considering your repo might contain submodules:
git submodule foreach --recursive 'git tag | xargs git tag -d'
(alternatively, "for i in `find .git -type d -name '*tags*'`; do rm -f $i/*; done")
git fetch -t
git submodule foreach --recursive git fetch -t
TortoiseGit can compare tags now.
Left log is on remote, right is at local.
Using the Compare tags feature of Sync dialog:
Also see TortoiseGit issue 2973
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