2D array in a struct - is is possible?

I am attempting to make a struct with a 2D array in it to store strings. But I keep getting a double free error when I execute the program

struct:

    struct room{
     开发者_如何学Python   int x;
        int y;
        char ** floor;
};

Here is my malloc:

struct room * newRoom = malloc(sizeof(struct room));
newRoom->floor = malloc(sizeof(char *) * height);
if(newRoom->floor == NULL || newRoom == NULL)
{
    printf("Room allocation failed \n");
}
for(i=0; i<width ;i++)
{
    newRoom->floor[i] = malloc(sizeof(char) * (width + 1));
    if(newRoom->floor[i] == NULL)
    {
        printf("Room string allocation failed \n");
    }
}

and my free, which is what seems to be causing the error:

for(i=0; i<size ;i++)
{
    free(toBeFreed->floor[i]);
}
free(toBeFreed->floor);
free(toBeFreed);

I don't really do much with the array other than fill it with characters (using for loops) and call mvprintw() so I don't think the problem is in between. What am I doing incorrectly?

Edit: so I should've clarified but width == height == size, the variables are in different files, so they do differ a little

EDIT2: apparently height != width, and I can't even keep my own variable name straight!

When allocating you use:

for(i=0; i<width ; i++)

When freeing, you use:

for(i=0; i<size ;i++)

If width != size, you're going to have issues.

for(i=0; i<width ;i++)

should be

for(i=0; i<height;i++)

right?

and

for(i=0; i<size ;i++)
{
    free(toBeFreed->floor[i]);
}

should be

for(i=0; i<height;i++)
{
    free(toBeFreed->floor[i]);
}

Also

malloc(sizeof(char) * (width + 2));

Where does the +2 come from?

Other than that it seems rather ok, can you supply code how you want to use it?