Printing same physical address in a c program
Is there is a way to print the same physical address in these programs (while using the shared memory concept) rather than printing different logical addresses?
The reason for me to print the same physical address :...
/*It's optional to read this, since I have provided a lot of information which is not to the core */
In my lab, I have two programs: one to store a string in a physical memory via shared memory concept and one to print the same string via accessing the shared memory.
Program 1:
#include<sys/types.h>
#include<string.h>
#include<sys/ipc.h>
#include<sys/shm.h>
#include<stdio.h>
main()
{
key_t key;
int shmid;
char* addr1;
key = ftok("/home/tamil/myc/pws.c",'T');
shmid = shmget(key,128*1024,IPC_CREAT|SHM_R|SHM_W);
addr1 = shmat(shmid,0,0);
printf("\nIPC SHARED MEMORY");
printf("\n SENDER ADDRESS");
printf("\nTHE ADDRESS IS %p",addr1);
printf("\nENTER THE MESSAGE:");
scanf("%s",addr1);
printf("\nMESSAGE STORED IN %p IS %s",addr1,addr1);
}
Program 2:
#include<sys/types.h>
#include<string.h>
#include<sys/ipc.h>
#include<sys/shm.h>
#include<stdio.h>
main()
{
int shmid;
char* addr1;
key_t key;
key = ftok("/home/tamil/myc/pws.c",'T');
shmid = shmget(key,128*1024,SHM_R|SHM_W);
addr1 = shmat(shmid,0,0);
printf("\nIPC SHARED MEMORY");
printf("\n SENDER ADDRESS");
printf("\nTHE ADDRESSS IS %p",addr1);
printf("\nMESSAGE STORED IN %p IS %s",addr1,addr1);
}
Output:
tamil@ubuntu:~/myc$ cc shmget.c
tamil@ubuntu:~/myc$ ./a.out
IPC SHARED MEMORY
SENDER ADDRESS
THE ADDRESS IS 0xb786c000
ENTER THE MESSAGE:helloworld
MESSAGE STORED IN 0xb786c000 IS helloworld
tamil@ubuntu:~/myc$ cc shmget2.c
tamil@ubuntu:~/myc$ ./a.out
IPC SHARED MEMORY
SENDER ADDRESS
THE ADDRESSS IS 0xb7706000
MESSAGE STORED IN 0xb7706000 IS helloworld
tamil@ubuntu:~/myc$
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Here these programs are printing the 2 different logical address. But (to satisfy the college professor) is there is a way to print the same physical address? Please help..
- Your programs are most likely already doing exactly what your professor asked you to do.
- You are totally not understanding the concept of physical vs. virtual addresses. On any operating system that uses virtual memory, a regular application (as opposed to the OS itself) can not know any physical addresses at all.
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