SQL grouping by parent child
If I had this structure with the columns:
Primary_Key, Name, Parent_Primary_ID, DISPLAY_ORDER
1 Event NULL 1开发者_运维问答
2 News NULL 2
3 Event_List 1 1
4 Event_Detail 1 2
5 News_List 2 1
6 News_Details 2 2
how would you return data like:
1 Event
3 Event_List
4 Event_Detail
2 News
5 News_List
6 News_Detail
Thanks Rob
If SQL Server 2005+
DECLARE @YourTable TABLE
(Primary_Key INT PRIMARY KEY,
Name VARCHAR(100),
Parent_Primary_ID INT NULL,
DISPLAY_ORDER INT)
INSERT INTO @YourTable
SELECT 1,'Event',NULL,1 UNION ALL
SELECT 2,'News',NULL,2 UNION ALL
SELECT 3,'Event_List',1,1 UNION ALL
SELECT 4,'Event_Detail',1,2 UNION ALL
SELECT 5,'News_List',2,1 UNION ALL
SELECT 6,'News_Details',2,2;
WITH Hierarchy
AS (SELECT *,
path = CAST(DISPLAY_ORDER AS VARCHAR(100))
FROM @YourTable
WHERE Parent_Primary_ID IS NULL
UNION ALL
SELECT y.Primary_Key,
y.Name,
y.Parent_Primary_ID,
y.DISPLAY_ORDER,
CAST(path + '.' + CAST(y.DISPLAY_ORDER AS VARCHAR) AS VARCHAR(100))
FROM @YourTable y
JOIN Hierarchy h
ON h.Primary_Key = y.Parent_Primary_ID)
SELECT Primary_Key,
Name
FROM Hierarchy
ORDER BY path
Try (asumming standardish sql is supported)
DECLARE @YourTable TABLE
(Primary_Key INT PRIMARY KEY,
Name VARCHAR(100),
Parent_Primary_ID INT NULL,
DISPLAY_ORDER INT)
INSERT INTO @YourTable
SELECT 1,'Event',NULL,1 UNION ALL
SELECT 2,'News',NULL,2 UNION ALL
SELECT 3,'Event_List',1,1 UNION ALL
SELECT 4,'Event_Detail',1,2 UNION ALL
SELECT 5,'News_List',2,1 UNION ALL
SELECT 6,'News_Details',2,2;
select
primary_key = t1.primary_key,
name = t1.name
from
@YourTable t1
left join @YourTable t2 on t1.parent_primary_id = t2.Primary_Key
order by
coalesce(t2.DISPLAY_ORDER,t1.DISPLAY_ORDER,0),
case
when t2.Primary_Key is null then 0
else t1.DISPLAY_ORDER
end
I don't see any grouping in your results. Unless you are trying to do something you aren't telling us I would use the query below:
SELECT Primary_Key, Name FROM YourTable
I don't see how you are ordering those results so I didn't try to order them.
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