Java blocking queue containing only unique elements
sort of like a "blocking set". How can I implement a blocking queue where adding a member that is already in the开发者_运维技巧 set is ignored?
I wrote this class to solve a similar problem:
/**
* Linked blocking queue with {@link #add(Object)} method, which adds only element, that is not already in the queue.
*/
public class SetBlockingQueue<T> extends LinkedBlockingQueue<T> {
private Set<T> set = Collections.newSetFromMap(new ConcurrentHashMap<>());
/**
* Add only element, that is not already enqueued.
* The method is synchronized, so that the duplicate elements can't get in during race condition.
* @param t object to put in
* @return true, if the queue was changed, false otherwise
*/
@Override
public synchronized boolean add(T t) {
if (set.contains(t)) {
return false;
} else {
set.add(t);
return super.add(t);
}
}
/**
* Takes the element from the queue.
* Note that no synchronization with {@link #add(Object)} is here, as we don't care about the element staying in the set longer needed.
* @return taken element
* @throws InterruptedException
*/
@Override
public T take() throws InterruptedException {
T t = super.take();
set.remove(t);
return t;
}
}
You can create a new class that composes a BlockingQueue, a Set, and a lock. When you put() you test against the set while holding a lock that prevents get() from running. When you get() you remove the item from the set so that it can be put() again in the future.
A blocking queue implementation backed by a linked hash set for predictable iteration order and constant time addition, removal and contains operations:
There you go.
You can override add and put methods of any implementation of BlockingQueue<T>
to check first if the element is already within the queue, e.g.
@Override
public boolean add(T elem) {
if (contains(elem))
return true;
return super.add(elem);
}
class BlockingSet extends ArrayBlockingQueue<E> {
/*Retain all other methods except put*/
public void put(E o) throws InterruptedException {
if (!this.contains(o)){
super.put(o);
}
}
}
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