How can I get a MMYYYY format in SQL Server?
Okay, the question is mildly misleading... I know a couple different ways to get the MMYYYY format from a date, but it requires converting the string into VARCHAR. While that's all fine and dandy, ordering the results is where it becomes a real pain.
Here's what I'm using:
SELECT
CONVERT(VARCHAR(2),MONTH(TransactionDte)) + '/' + CONVERT(VARCHAR(4),YEAR(TransactionDte) AS MMYYYY
,SUM(TransactionCt) AS TransCt
,SUM(TransactionAmt) AS TransAmt
FROM Transactions
GROUP BY CONVERT(VARCHAR(2),MONTH(TransactionDte)) + '/' + CONVERT(VARCHAR(4),YEAR(TransactionDte)
The results appear as follows:
1/2010 1/2011 10/2010 10/2011 11/2010 11/2011 12/2010 12/2011 2/2010 2/2011 3/2010 3/2011 etc...I'm trying them to order by the date ascending. As you can see, they do not... Is ther开发者_开发问答e a way to get what I'm trying to achieve?
Thanks in advance!
what is wrong with
ORDER BY TransactionDte DESC
or even
order by CONVERT(VARCHAR(4),YEAR(TransactionDte) + CONVERT(VARCHAR(2),MONTH(TransactionDte)) DESC
Try this method:
RIGHT(CONVERT(VARCHAR(10), TransactionDte, 103), 7) AS [MM/YYYY]
If you want it without the /
then use this:
REPLACE(RIGHT(CONVERT(VARCHAR(10), TransactionDte, 103), 7),'/','') AS [MMYYYY]
;WITH t AS
(
SELECT GETDATE() AS TransactionDte UNION ALL
SELECT GETDATE()+1 AS TransactionDte UNION ALL
SELECT GETDATE()+90
)
SELECT CONVERT(VARCHAR(2),MONTH(TransactionDte)) + '/' +
CONVERT(VARCHAR(4),YEAR(TransactionDte)) AS MMYYYY,
COUNT(*)
FROM t
GROUP BY MONTH(TransactionDte), YEAR(TransactionDte)
ORDER BY MIN(TransactionDte)
SELECT
MM/YYYY
,TransCt
,TransAmt
FROM
(SELECT
DATEPART(MM, TransactionDte) AS TransMonth
,DATEPART(YYYY,TransactionDte) AS TransYear
,RIGHT(CONVERT(VARCHAR(10), TransactionDte, 103), 7) AS [MM/YYYY]
,SUM(TransactionCt) AS TransCt
,SUM(TransactionAmt) AS TransAmt
FROM Transactions
GROUP BY
DATEPART(MM, TransactionDte)
,DATEPART(YYYY,TransactionDte) AS TransYear
,RIGHT(CONVERT(VARCHAR(10), TransactionDte, 103), 7)
) T
ORDER BY TransYear,TransMonth
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