Perl - pass code block as parameter inside parentheses

Is it possible to pass a block of code to a sub using "parentheses" syntax?

I.e. when i write

List::MoreUtils::any { defined ($_) } (undef, undef, 1);

it works. But when i try to add parentheses

List::MoreUtils::any ( { defined ($_) } , (undef, undef, 1) );

this is interpreted as an an开发者_JAVA技巧onymous hash, giving an error message. Neither escaping nor using eval helps.

The idea behind all the fuss is if the call is a part of an expression, i.e.

if (first_index { defined (${$_})} $jms_positions > $jms_positionals_seen )

some operator following the arguments might be executed before the call, producing an undesired result.

An anonymous subroutine is declared with the syntax

sub { say "The sub with no name!" };

Perl's prototype system allows a special exception where a code block is the first parameter, in which case you can leave off the leading sub and just pass the block, similar to a Perl builtin. But this only works when calling it in the parentheses-less style. Using parens causes the parser to think you want to pass a hash-ref.

So you can say

List::MoreUtils::any( sub { defined }, undef, undef, 1 );

If you insist on using parens.

No, only for the builtins.

$ perl -ce'map({ "..." } @a)'
-e syntax OK

$ perl -ce'grep({ "..." } @a)'
-e syntax OK

$ perl -ce'sub f(&@); f { "..." } @a'
-e syntax OK

$ perl -ce'sub f(&@); f({ "..." } @a)'
Array found where operator expected at -e line 1, near "} "
        (Missing operator before  ?)
syntax error at -e line 1, near "} @a"
-e had compilation errors.

Adding parens around the whole call is usually a suitable workaround.

( any { defined } (undef, undef, 1) )

Just insert sub:

List::MoreUtils::any ( sub { defined ($_) } , (undef, undef, 1) );