PHP MySQL single column/row display?
$row = mysql_fetch_array(mysql_query("SELECT * FROM persons WHERE id = '$id'"));
echo $row['name'];
But that din't work, any other way to simply show only one result?
Thanks in advance![EDIT:]
(I'm using PHP 5.3)<?php
include("connection.php");
$id = $_GET['deletid'];
$result = mysql_query("SELECT * FROM persons WHERE id = '$id' LIMIT 1");
if(!$result){
echo mysql_error();
}
if ($row = mysql_fetch_array($result)){
开发者_如何学JAVA echo $row['name'];
}
echo "<p>id:$id</p>";
?>
If you need just the name and you need just one result you should rewrite your query as follow:
$row = mysql_fetch_array(mysql_query("SELECT name FROM persons WHERE id = '". (int) $id ."' LIMIT 1"));
Now to get the result you should just get it with a
$row['name'];
EDIT Now that you posted your entire code i got what's wrong: You are deleting that result before getting its name. Basically you delete that user and then you attempt to get its name. EDIT
<?php
include("connection.php");
if (empty($_GET['deleteid'])) {
exit('"deleteid" is empty');
}
$id = mysql_real_escape_string($_GET['deletid']);
$result = mysql_query("SELECT name FROM persons WHERE id = '". (int) $id ."' LIMIT 1");
if(!$result){
echo mysql_error();
}
$row = mysql_fetch_assoc($result); // for just one result you don't need of any loop
echo $row['name'];
echo "<p>id:". htmlspecialchars($id) ."</p>";
?>
try
$row = mysql_fetch_array(mysql_query("SELECT name FROM persons WHERE id = ". (int) $id));
echo $row['name'];
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