Find string and replace each occurance with different string

I am looking for a simple batch solution for the following:

In a number of files I want to replace a string with another one. Can do this with 开发者_开发百科Notepad++. However, each new string has to be unique, read from a list of new strings.

So, if 'abc' occurs in some files, and I have a list with new strings, replace it this way:

abc --> alex

abc --> ben

abc --> chris

abc --> dave

etc.

I can have a txt file with the new strings to read from.

Hope someone has a solution for me!

Many thanks, Lennart

Would a Perl script work?

my @words = qw(alex ben chris dave ...);

while (<>) {
    s/abc/shift @words/ge;
    print;
}

If you want the word list to loop:

my @words = qw(...);
my $i = 0;

while (<>) {
    # I know I should have written this in a more readable way...
    s{abc}{$words[$i++] // $words[$i=0]}ge;
    print;
}

Or as batch script

@echo off
setlocal Disabledelayedexpansion
set "wordlist=alex ben chris dave"
for /F "tokens=* delims=" %%a in (myFile.txt) do (
    set "line=%%a"
    setlocal Enabledelayedexpansion
    for /F "tokens=1,*" %%b in ("!wordlist!") do (
        set "newline=!line:abc=%%b!"
        (echo(!newline!)
        if !newline! NEQ !line! (
            endlocal
            set "wordlist=%%c"
        ) ELSE ( 
            endlocal 
        )
    )   
)

Edit Change to a "!" safe variant

Try and find a sed executable for Windows which supports the -i (--inline) switch and your job will become a toddler's task!