R function to create band matrix
I need to write two functions toBand()
and replaceBand()
:
test3 <- toBand(test1,3)
test4 <- replaceBand(test1, toBand(test2,3))
to get the output below.
The first returns a matrix of the diagonal and co-diagonal elements, using the lower triangle of X. The second replaces the corresponding elements in X from the data in the band matrix supplied. The function then returns the modified X.
Are there any packages that I can use to do this? Any suggestions on how to do this?
Thank you
> test1
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] "a11" "a21" "a31" "a41" "a51" "a61"
[2,] "a21" "a22" "a32" "a42" "a52" "a62"
[3,] "a31" "a32" "a33" "a43" "a53" "a63"
[4,] "a41" "a42" "a43" "a44" "a54" "a64"
[5,] "a51" "a52" "a53" "a54" "a55" "a65"
[6,] "a61" "a62" "a63" "a64" "a65" "a66"
> test2
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] "*a11*" "*a21*" "*a31*" "*a41*" "*a51开发者_运维技巧*" "*a61*"
[2,] "*a21*" "*a22*" "*a32*" "*a42*" "*a52*" "*a62*"
[3,] "*a31*" "*a32*" "*a33*" "*a43*" "*a53*" "*a63*"
[4,] "*a41*" "*a42*" "*a43*" "*a44*" "*a54*" "*a64*"
[5,] "*a51*" "*a52*" "*a53*" "*a54*" "*a55*" "*a65*"
[6,] "*a61*" "*a62*" "*a63*" "*a64*" "*a65*" "*a66*"
> test3
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] "a11" "a22" "a33" "a44" "a55" "a66"
[2,] "a21" "a32" "a43" "a54" "a65" NA
[3,] "a31" "a42" "a53" "a64" NA NA
[4,] "a41" "a52" "a63" NA NA NA
> test4
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] "*a11*" "*a21*" "*a31*" "*a41*" "a51" "a61"
[2,] "*a21*" "*a22*" "*a32*" "*a42*" "*a52*" "a62"
[3,] "*a31*" "*a32*" "*a33*" "*a43*" "*a53*" "*a63*"
[4,] "*a41*" "*a42*" "*a43*" "*a44*" "*a54*" "*a64*"
[5,] "a51" "*a52*" "*a53*" "*a54*" "*a55*" "*a65*"
[6,] "a61" "a62" "*a63*" "*a64*" "*a65*" "*a66*"
This is straightforward if you don't need to use the output from toBand
:
replaceBand <- function(a, b, k) {
swap <- abs(row(a) - col(a)) <= k
a[swap] <- b[swap]
a
}
Making the matrices to demonstrate:
test1 <- matrix(ncol=6, nrow=6)
test1 <- matrix(paste("a", row(test1), col(test1), sep=""), nrow=6)
test1b <- matrix(paste("a", col(test1), row(test1), sep=""), nrow=6)
test1[upper.tri(test1)] <- test1b[upper.tri(test1b)]
test2 <- matrix(paste("*", test1, "*", sep=""), nrow=6)
The output is exactly as desired:
> replaceBand(test1, test2, 3)
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] "*a11*" "*a21*" "*a31*" "*a41*" "a51" "a61"
[2,] "*a21*" "*a22*" "*a32*" "*a42*" "*a52*" "a62"
[3,] "*a31*" "*a32*" "*a33*" "*a43*" "*a53*" "*a63*"
[4,] "*a41*" "*a42*" "*a43*" "*a44*" "*a54*" "*a64*"
[5,] "a51" "*a52*" "*a53*" "*a54*" "*a55*" "*a65*"
[6,] "a61" "a62" "*a63*" "*a64*" "*a65*" "*a66*"
Here are versions of toBand
and replaceBand
that work as described. I imagine it would be cleaner to do the arithmetic to figure out exactly how to fill in the matrices, but this is a way to do it without having to think very hard. Perhaps someone else will answer it that way.
toBand <- function(x,k) {
n <- nrow(x)
out <- matrix(nrow=n, ncol=n)
out[row(out) + col(out) - 1 <= n] <- x[lower.tri(x, diag=TRUE)]
out[1:(k+1),]
}
replaceBand <- function(a, b) {
b[row(b)+col(b)-1 <= ncol(b)]
swap <- abs(row(a) - col(a)) <= nrow(b) - 1
a[swap & lower.tri(a, diag=TRUE)] <- b[row(b)+col(b)-1 <= ncol(b)]
a[upper.tri(a)] <- t(a)[upper.tri(a)]
a
}
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