For Loop to do repetitive checking of variables for me

NSArray *test = [NSArray arrayWithObjects:@"22", @"3", @"22", @"5", @"1", @"0", @"2", nil];

NSArray *test2 = [NSArray arrayWithObjects:@"21", @"2", @"20", @"5", @"1", @"9", @"2", nil];

for(int i = 0; i < 7; i++) {

   if ([test objectAtIndex:i] == [test2 objectAtIndex:i]); {

testVariable = testVariable + 1; 
    }

}    

NSLog(@"%i", testVariable);    

I tried the above code to test comparison of variables but it returns 7 when it should return 3. Do I need to somehow retrieve and store each array object in a local variable and compare thos against each other? Or can I do something more direct like what I tri开发者_StackOverflow社区ed above. Arrays are very interesting. :)

UPDATE:

Got it to work with NSInteger.. :) Guess I was comparing objects and not the actual integer numbers before..

You can use preprocesor

#define variable(name,number) {name##number}

and later in the loop

for (int a = 1; a <= 53; a++) {    
    if ((variable(taken,a) == 2) && (variable(hidden,a) == 2)) {
        //Do something
    } 
}

The simple answer is not to use different variables. Use a collection or an array instead. Then you could have:

if (taken[a] == 2 && hidden[a] == 2) {
    ...
}

Think of using an array whenever you find yourself putting numeric suffixes on variables of the same type and prefix.