How can I modify the result of a method call on a mocked object before it is returned?
Given the following streamlined example, using RhinoMocks and MSpec:
[Subject(typeof (LocationController))]
public class when_creating_a_location_with_invalid_model : context_for_location_controller
{
static LocationModel model = new LocationModel();
static SelectList states = new SelectL开发者_StackOverflow社区ist(new Dictionary<string,string> {
{ "IN", "Indiana" }, { "NY", "New York" }
});
static ActionResult result;
Establish context = () =>
{
LocationModelBuilder.Stub(x =>
x.Build(Arg<LocationModel>.Is.Equal(model))).Return(model);
}
Because of = () => result = subject.Create(model);
It should_automatically_select_a_state = () => result.Model<LocationModel>()
.States.ShouldNotBeEmpty();
}
How can I modify the object contained in the model variable before it is returned from the stubbed call of LocationModelBuilder.Build()? I want to perform an assignment like model.States = states
just before return on Build(). I tried playing with the Do() handler but I give up...
Try using WhenCalled(). The parameter to WhenCalled allows access to the mocked method's arguments and you can also set the return value.
.WhenCalled(m => {
Model model = (Model) m.Arguments[0];
model.States = ...;
});
精彩评论