JavaScript: how to get img and div elements using getElementsByTagName
I have a tree structure as follows:
<ul id="theul275">
<li>
<div id="red"></div>
<img id="green" />
<script></script>
<div id="blue"></div>
</li>
</ul>
There are multiple UL's likes this on my page each with a different id. I am getting each UL by doing this:
var child = document.getElementById('theul' + id).getElementsByTagName('*');
the problem is, I only want to get the children of each ul which are either div's or img's. Is there a way to get elements by multiple tag names?
I really appreci开发者_如何学Goate any help because I am kind of new to JavaScript! Thanks!
Depending on what browsers you may to support, you could use the CSS selector interface.
document.getElementById('theul275').querySelectorAll('div, img');
Or use a library. There are plenty of options out there. I am familiar with two,
MooTools
$('theul275').getElements('div, img');
jQuery
$('#theul275').find('div, img');
Or get a reference to the li
node, and loop through each node and check if the nodeName is DIV
or IMG
.
for (var i = 0, l = child.length; i < l; i++)
{
if (child[i].nodeName == 'DIV' || child[i].nodeName == 'IMG')
{
//...
}
}
You could use a iterative method for this.
var elemArray = document.getElementById('theul' + id).childNodes,
getChildByNodeName = function (elem, pattern) {
var childCollection = [],
re = new RegExp(pattern, 'g'),
getChild = function (elements) {
var childs = elements.childNodes,
i = 0;
if (childs) {
getChild(childs);
for (i = 0; i < childs.length; i += 1) {
if (childs[i].nodeName.match(pattern)) {
childCollection.push(childs[i]);
}
}
}
};
getChild(elem);
return childCollection;
}
var childs2 = getChildByNodeName(elemArray, '^(DIV|IMG)$'); // array of match elements
And just change the pattern ('^(DIV|IMG)$'
) to suite your needs.
If you can use jQuery, try
var child = $("#theul" + id).find("div,img");
Otherwise, see JavaScript NodeList.
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