Select every nth item in jQuery?

jQuery has the handy :even and :odd selectors for selecting the even- or odd-indexed items in a set, which I'm using to clear every other item in a series of floated boxes, as f开发者_如何转开发ollows:

<div class='2up'>
   <div> ... </div>
   <div> ... </div>
   ...
   <div> ... </div>
</div>

and

// Clear every 2nd block for 2-up blocks
$('.2up>div:even').css("clear", "both");

This works like a charm.

My question: Is there a straightforward way in jQuery to select every third or fourth item, so I could do the same thing with 3-up or 4-up items?

Try:

$("div:nth-child(3n+1)").css("clear", "both");

You could use the :nth-child(index/even/odd/equation) selector. http://docs.jquery.com/Selectors/nthChild#index

you can use the :nth-child(index/even/odd/equation) selector.

Example:

<div class='5up'>
   <div> ... </div>
   <div> ... </div>
   ...
   <div> ... </div>
</div>

// Clear every 5th block for 5-up blocks
$('.5up>div:nth-child(5n)').css("clear", "both");

// Clear after every 5th block for 5-up blocks
// note: This will also clear first block.
$('.5up>div:nth-child(5n+1)').css("clear", "both");

No, not as such. The filter function will let you do that though.

EDIT:

I stand corrected. Use the n-th child function for simplicity.