How do late static bindings work in this scenario?
The following code outputs 'x as set in class A', h开发者_如何学JAVAow would I make it output 'x as set in class B' without changing class B?
<?php
class A
{
public static $x = 'x as set in class A';
public static function getX()
{
return self::$x;
}
}
class B extends A
{
public static $x = 'x as set in class B';
}
echo B::getX();
self
always refers to the class, where it is defined. What you are looking for is "Late Static Binding" (as you already suggest, but dont use). The static
keyword within a code block refers to the "actual" class, means: Either the called class (XY::method()
), or the class of the called object ($x->method()
).
return static::$x;
The static
keyword at the property declaration has nothing to to with LSB. It is just the common declartion for class properties.
Note, that LSB is not available in PHP<5.3
精彩评论