Basic PHP problems

When I use this function variables created by the included scripts are retained within the scope of this function.

function reqscript($script)
{
    $include_dir = 'inc/';
    $page_ext = '.php';
    include($include_dir.$script.$page_ext);
}

Is开发者_运维知识库 there any way of me not having to use the following method?

include(buildfilename('...'));

If you want to define some variables in your included file, you have to use $GLOBALS.

e.g: $foobar = 42; should be $GLOBALS['foobar'] = 42;

So $foobar is available in the global scope (outside of functions).

But I would prefer a buildfilename() method.

Your answer is on php.net already, use return at the end of your included file.

http://php.net/manual/en/function.include.php

Example #5:

return.php

<?php

$var = 'PHP';

return $var;

?>

noreturn.php

<?php

$var = 'PHP';

?>

testreturns.php

<?php

$foo = include 'return.php';

echo $foo; // prints 'PHP'

$bar = include 'noreturn.php';

echo $bar; // prints 1

?>

I suggest you adopt your code to use the buildfilename() method, like Floem suggested. However, if you can't or do not wish to do so, here's a simple wrapper to import variables to the global namespace:

class Req {
    public function __construct($src) {
        include($src);
        foreach (get_object_vars($this) as $name => $value) {
            $_GLOBALS[$name] = $value;
        }
    }
}

function reqscript($script) {
    $include_dir = 'inc/';
    $page_ext = '.php';
    new Req($include_dir . $script . $page_ext);
}