JQuery append() DIV HTML without <img>
Been trying to find an answer to this but can't seem to get my head around it:
var newLayout = '<div id="blog-left"></div>' ; // This creates the layout the content will be moved to
newLayout += '<div id="blog-right" class="nivoSlider"></div>' ;
newLayout += '<div style="clear:both;"></div>' ;
newLayout += '<div id="img-temp" style="display:none;"></div>' ;
$('.blog').append(newLayout); // Add the new layout
$('#blog-left').append( $('.blog p') ); // All <p>'s being added to the new layout
$('#blog-right').app开发者_Go百科end( $('.blog img') ); // All <IMG>'s being added to the new layout
This work really well, however the problem I have is instead of appending the <p>
to #blog-left
I want to append all the contained HTML
but minus the <IMG>
tags. So all HTML
goes into #blog-left
and <IMG>
's go into #blog-right.
I've tried using .html()
which works to a point but the #blog-left
& #blog-right
are in the containing div .blog
.
I've tried a couple of things but nothing returns correctly if at all. So do any of you bright sparks have the solution using JQuery?
Thanks in advance.
Sam T.
I would do it like so:
var $blog = $('.blog');
// first add all images to right (removes them from .blog)
var $right = $('<div id="blog-right" class="nivoSlider" />')
.append($blog.find('img'));
// add all remaining elements from .blog to left
var $left = $('<div id="blog-left" />').append($blog.children());
var container = '<div style="clear:both;"></div>' +
'<div id="img-temp" style="display:none;"></div>';
// add the new content to .blog
$blog.append($left).append($right).append(container);
Try this to filter out img tags.
var $blog = $('.blog');
$blog.append(newLayout);
var $p = $blog.find("p");
var $img = $blog.find("img");
$('#blog-left').append($p);
$('#blog-right').append($img);
Example on jsfiddle.
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