While loop in Bash script?

I'm not used to writing Bash scripts, and Google didn't help in figuring out what is wrong with this script:

#!/bin/bash
while read myline
do
done

echo "Hello"
while read line
do
done

exit 0

The output I get is:

./basic.agi: line 4: syntax error near unexpected token 'done'
./basic.agi: line 4: 'done'

and my bash version is:

GNU bash, version 3.2.25(1)-release (i686-redhat-linux-gnu)

Thank you.

Edit: The script works OK when the while loop isn't empty.

While I'm at it... I expected to exit the loop when the user typed nothing, ie. simply hit the Enter key, but Bash keeps looping. How can I exit the loop?

whi开发者_Python百科le read myline
do
        echo ${myline}
done

echo "Hello"
while read line
do
        true
done

exit 0

You can't have an empty loop. If you want a placeholder, just use true.

#!/bin/bash
while read myline
do
    true
done

or, more likely, do something useful with the input:

#!/bin/bash
while read myline
do
    echo "You entered [$line]"
done

As for your second question, on how to exit the loop when the user just presses ENTER with nothing else, you can do something:

#!/bin/bash
read line
while [[ "$line" != "" ]] ; do
    echo "You entered [$line]"
    read line
done

When you are using the read command in a while loop it need input:

echo "Hello" | while read line ; do echo $line ; done

or using several lines:

echo "Hello" | while read line
    do
    echo $line
done

This is a way to emulate a do while loop in Bash, It always executes once and does the test at the end.

while
    read -r line
    [[ $line ]]
do
    :
done

When an empty line is entered, the loop exits. The variable will be empty at that point, but you could set another variable to its value to preserve it, if needed.

while
    save=$line
    read -r line
    [[ $line ]]
do
    :
done

What are you trying to do? From the look of it it seems that you are trying to read into a variable?

This is done by simply stating read the value can then be found inside of $

ex:

read myvar

echo $myvar

As other have stated the trouble with the loop is that it is empty which is not allowed.

If you are looking to create a menu with choices as a infinite loop (with the choice to break out)

PS3='Please enter your choice: '
options=("hello" "date" "quit")
select opt in "${options[@]}"
do
    case $opt in
        "hello") echo "world";;
        "date") echo $(date);;
        "quit")
            break;;
        *) echo "invalid option";;
    esac
done

PS3 is described here

If you type help while in bash you'll get an explanation of the command.