Quick question on If(!x()) where x() is a function

Guys, I am not exactly sure what happens here for the if statement. I did a bunch of google sea开发者_高级运维rches, but nothing comes up. Obviously, the function x() returns something. Either a 1 or a 0. But I am not sure what it does. Is it short hand for x() == 0 or x() == 1. I am just going over coding examples and I noticed it.

if(!x())
{
   // executes if x() is 0
   // x() == 0
}

if(x())
{
   // executes if x() is non-0
   // x() != 0
}

It is short hand for if(x()==0){ // stuff }

Note that x() does not have to return only '0' or '1'. In C, any non-zero value is considered TRUE in a conditional statement and the negation of any non-zero value is ZERO.

if(!x()) just checks if x() returns something that evaluates to false, in other words if(x() == false) or if(x() == 0) is the same.

That means x() == 0. And if (x()) means if (x()!=0)

In C, 0 is considered false and all other numbers are considered true. In you if-statement, you are saying "if x() is not true" which is equivalent to "if x() is false". Therefore, if(!x()) is the same thing as if(x()==0).