boost-units - using a dimensionless type of arbitrary system
I am trying to make a dimensioned vector class with boost-units like so,
//vector will be constructed vec<si::length> v(10, 1.0*si::metre);
template<typename dimension>
class vec
{
public:
//constructor setting all values to q.
vec(const size_t, const boost::units::quantity<dimension> q)
//etc
}
It all works fine except for the operator*=
and operator/=
that do element wise multiplication and division. Since these do not change the dimension, they only make sense when multiplying/dividing by a dimensionless quantity: I am struggling to find an arbitrary dimensionless quantity that is not locked into a specific system (e.g. si or cgs units).
I want something like,
开发者_运维知识库/** Multiply a dimensionless vector. */
vec<dimension>&
operator*=(const vec<boost::units::dimensionless_type>& b);
or perhaps some metaprogramming magic (I notice boost::units::is_dimensionless exists, but I have no idea how to use it as I am not versed in general metaprogramming techniques)
template<typename dimension>
template<typename a_dimensionless_type>
vec<dimension>&
vec<dimension>::operator*=(const vec<a_dimensionless_type>& b){
//some compile time check to make sure that a_dimensionless_type is actually dimensionless?
//the rest of the function
}
I want following examples to compile
vec<si::dimensionless> d(10, 2.0);
vec<si::length> l(10, 2.0*si::metre);
l*=d;
vec<cgs::dimensionless> d2(10, 2.0);
vec<cgs::length> l2(10, 2.0*cgs::centimetre);
l2*=d2;
Okay, after examining the library details (and learning about BOOST_MPL_ASSERT) it turned out to be very easy. My compliments to the library designer.
template<typename a_dimensionless_type>
vec<dimension>&
operator*=(const vec< a_dimensionless_type >& b)
{
BOOST_MPL_ASSERT(( boost::units::is_dimensionless<boost::units::quantity<a_dimensionless_type> > ));
//the rest of the function
};
I might be mistaken about Boost details, but conventionally double
is the dimensionless type.
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