problem with comparing a name from getter method to user input string

i'm having trouble comparing in my if statement, in C programming i am using "==" double equal sign to compare two string...

how about comparing a string using getter method to a new string... i try to use the double equal sign but i was prompted to change it into this:

if (entry[i].getName().equals(EName))

by the way this is my whole code:

import javax.swing.JOptionPane;
import javax.swing.JTextArea;

public class AddressBook {

    private AddressBookEntry entry[];
    private int counter;
    private String EName;

    public static void main(String[] args) {
        AddressBook a = new AddressBook();
        a.entry = new AddressBookEntry[100];
        int option = 0;
        while (option != 5) {
            String content = "Choose an Option\n\n"
                    + "[1] Add an Entry\n"
                    + "[2] Delete an Entry\n"
                    + "[3] Update an Entry\n"
                    + "[4] View all Entries\n"
                    + "[5] View Specific Entry\n"
                    + "[6] Exit";
            option = Integer.parseInt(JOptionPane.showInputDialog(content));
            switch (option) {
                case 1:
                    a.addEntry();
                    break;
                case 2:

                    break;
                case 3:
                    a.editMenu();
                    break;
                case 4:
                    a.viewAll();
                    break;
                case 5:
                    break;
                case 6:
                    System.exit(1);
                    break;
                default:
                    JOptionPane.showMessageDialog(null, "Invalid Choice!");
            }
        }
    }

    public void addEntry() {
        entry[counter] = new AddressBookEntry();
        entry[counter].setName(JOptionPane.showInputDialog("Enter name: "));
        entry[counter].setAdd(JOptionPane.showInputDialog("Enter add: "));
        entry[counter].setPhoneNo(JOptionPane.showInputDialog("Enter Phone No.: "));
        entry[counter].setEmail(JOptionPane.showInputDialog("Enter E-mail: "));
        counter++;
    }

    public void viewAll() {
        String addText= "";
        for (int i = 0; i <  counter; i++) {
            addText = addText+(i+1)+ entry[i].getInfo()+ "\n";
        }
        JOptionPane.showMessageDialog(null, new JTextArea(addText));
    }

    public void editMenu() {
        int option = 0;
        while (option != 6) {
            String content = "Choose an Option\n\n"
                    + "[1] Edit Name\n"
                    + "[2] Edit Address\n"
                    + "[3] Edit Phone No.\n"
                    + "[4] Edit E-mail address\n"
                    + "[5] Back to Main Menu";
            option = Integer.parseInt(JOptionPane.showInputDialog(content));
            switch (option) {
                case 1:
                    editName();
                    break;
                case 2:
                    editAdd();
                    break;
                case 3:
                    editPhoneNo();
                    break;
                case 4:
                    editEmail();
                    break;
                case 5:
                    return;
                default:
                    JOptionPane.showMessageDialog(null, "Invalid Choice!");
            }
        }
    开发者_JAVA技巧}

    public void editName() {
        EName = JOptionPane.showInputDialog("Enter name to edit: ");
        for (int i = 0; i < counter; i++) {
            if (entry[i].getName().equals(EName)) {
                //JOptionPane.showMessageDialog(null, "found");
                entry[i].setName(JOptionPane.showInputDialog("Enter new name: "));
            }else {
                JOptionPane.showMessageDialog(null, "Entered Name not Found!");
            }
        }
    }

    public void editAdd() {
        EName = JOptionPane.showInputDialog("Enter name to edit: ");
        for (int i = 0; i < counter; i++) {
            if (entry[i].getName().equals(EName)) {
                //JOptionPane.showMessageDialog(null, "found");
                entry[i].setAdd(JOptionPane.showInputDialog("Enter new Address: "));
            }else {
                JOptionPane.showMessageDialog(null, "Entered Name not Found!");
            }
        }
    }

    public void editPhoneNo() {
        EName = JOptionPane.showInputDialog("Enter name to edit: ");
        for (int i = 0; i < counter; i++) {
            if (entry[i].getName().equals(EName)) {
                //JOptionPane.showMessageDialog(null, "found");
                entry[i].setPhoneNo(JOptionPane.showInputDialog("Enter new Phone No.: "));
            }else {
                JOptionPane.showMessageDialog(null, "Entered Name not Found!");
            }
        }
    }

    public void editEmail() {
        EName = JOptionPane.showInputDialog("Enter name to edit: ");
        for (int i = 0; i < counter; i++) {
            if (entry[i].getName().equals(EName)) {
                //JOptionPane.showMessageDialog(null, "found");
                entry[i].setEmail(JOptionPane.showInputDialog("Enter new E-mail add: "));
            }else {
                JOptionPane.showMessageDialog(null, "Entered Name not Found!");
            }
        }
    }
}

and this is my other class:

public class AddressBookEntry {

    private String name;
    private String add;
    private String phoneNo;
    private String email;
    private int entry;

    public String getAdd() {
        return add;
    }

    public String getEmail() {
        return email;
    }

    public int getEntry() {
        return entry;
    }

    public String getName() {
        return name;
    }

    public String getPhoneNo() {
        return phoneNo;
    }

    public void setAdd(String add) {
        this.add = add;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public void setEntry(int entry) {
        this.entry = entry;
    }

    public void setName(String name) {
        this.name = name;
    }

    public void setPhoneNo(String phoneNo) {
        this.phoneNo = phoneNo;
    }

    public String getInfo() {
        String Info = "NAME\tADDRESS\tPHONE NO.\tE-MAIL ADD\n"
                + name + "\t " + add + "\t " + phoneNo + "\t " + email + "\n";
        return Info;
    }

    public String getInfo2() {
        String content = "INFORMATION:\n\n"
                + "Name: " + name + "\n"
                + "Address: " + add + "\n"
                + "Tel. No: " + phoneNo + "\n"
                + "Email Add: " + email + "\n\n";
        return content;
    }
}

PLEASE PARDON MY CODE... i am new at java.... please help....

what i want to is traverse to all the array and edit the specific detail if the user input was equals to the entry[i].getName()

thanks a lot in advance...

Use equals() if you want to compare the representation of the string and not its object identity.

Assume we have: String s = "hello";

s == s
=> true // they are the *same* object
"hello" == new String("hello") // see comment below...
=> false // they are different objects representing the same string of text
"hello".equals("hello")
=> true
s.equals("hello")
=> true

There are at least 3 things to understand:

Java: == tests whether two references point to the same object, whereas equals tests whether two objects have the same content. So, even if two Strings have the same content, == may give false whereas s1.equals(s2) will give true. You can find loads about this on google.

C: In C, you shouldn't compare two strings using == either. Strings in C generally are char* (or const char*), and you should compare them with strcmp (or else you will run into the same problems as in Java).

C++: instances of std::string can be compared using ==.