How to do non-perspective image warping in OpenCV?
What you're trying should work. Calculate the homography by making the 4 corners of the polygon correspond to (0,0) (0,height) (width,0) and (width,height).
Have a look at GetPerspectiveTransform
I think what you want is a reversal of perspective transform.
Here is what you must consider doing. Assume that you had the polygon at locations (x1,y1)....(x4,y4) originally on your screen (0,0) ....(w,h). Applying perspective transform using cvWarpPerspective/getPerspectiveTransform you would be able to get the original co-ordinates to the known co-ordinates. So you should basically multiply the known co-ordinates with the inverse of the perspective transform matrix (unless that is non-invertible, in which case you must add a delta term to the homogeneous -coordinate term )
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